Q1. [1] § Chapter Introduction § 11.1 ELECTRIC CURRENT AND CIRCUIT § 11.7.1 Practical Applications of Heating Effect of Electric Current
An electric bulb is connected to a power supply of 220 V. If the current drawn by the bulb from the supply is 500 mA, the power of the bulb is :
- (A) 11 W
- (B) 110 W
- (C) 220 W
- (D) 1100 W
Previously asked in CBSE board exam
2025 31/2/1 Q14
Generated by claude-sonnet-4-6 · 2026-06-15 06:43 · grounding rag
Model Answer
(B) 110 W
P = VI = 220 V × 500 mA = 220 × 0.5 A = 110 W.
Explanation
Use P = VI. Convert 500 mA to 0.5 A before multiplying. This matches Example 11.12 in the textbook exactly. Examiners expect the formula, substitution, and unit.
If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website:
cbse.gov.in.