Q1. [1]
An electric bulb is connected to a power supply of 220 V. If the current drawn by the bulb from the supply is 500 mA, the power of the bulb is :
- (A) 11 W
- (B) 110 W
- (C) 220 W
- (D) 1100 W
Previously asked in CBSE board exam
2025 31/2/1 Q14
Generated by claude-sonnet-4-6 · 2026-06-15 06:43 · grounding rag
Model Answer
(B) 110 W
P = VI = 220 V × 500 mA = 220 × 0.5 A = 110 W.
Explanation
Use P = VI. Convert 500 mA to 0.5 A before multiplying. This matches Example 11.12 in the textbook exactly. Examiners expect the formula, substitution, and unit.
If a question refers to an image, map, graph or diagram that is not shown here, open the Study Guide single page app, go to
Library and find the actual CBSE question paper. The original papers are also available on the CBSE website:
cbse.gov.in.