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Science (086) — CBSE Class 10 board question

Q1. [5] § 4.2.1 Saturated and Unsaturated Carbon Compounds § 4.2.2 Chains, Branches and Rings § 4.4 SOME IMPORTANT CARBON COMPOUNDS – ETHANOL AND ETHANOIC ACID
Attempt either (a) or (b) : (b) (i) Write the structural formula of benzene. (ii) State the reason why carbon can neither form C⁴⁺ cation nor C⁴⁻ anion. (iii) What type of bond is formed between carbon and hydrogen ? (iv) How is ethanol converted to ethanoic acid ? (v) Complete the following chemical equation : CH₃COOC₂H₅ + NaOH ⎯⎯→
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2026 31/2/1 Q29 (b)
Generated by claude-sonnet-4-6 · 2026-06-15 06:46 · grounding rag
Model Answer

(i) Structural formula of benzene (C₆H₆):

Benzene has a ring of 6 carbon atoms with alternating double bonds:

$$\text{Hexagonal ring with alternating single and double bonds between carbon atoms, each C bonded to one H}$$

(A regular hexagon with alternating double bonds, each carbon bonded to one H atom.)

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(ii) Carbon has 4 electrons in its outermost shell. To form C⁴⁺, it would need to lose 4 electrons, requiring a very large amount of energy. To form C⁴⁻, it would gain 4 electrons, which would be difficult to hold in the nucleus with only 6 protons. Both processes are energetically unfavourable, so carbon forms covalent bonds instead.

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(iii) The bond formed between carbon and hydrogen is a covalent bond (non-polar covalent bond), formed by equal sharing of electrons.

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(iv) Ethanol is converted to ethanoic acid by oxidation, using an oxidising agent such as alkaline KMnO₄ or acidified K₂Cr₂O₇.

$$\text{CH}_3\text{CH}_2\text{OH} \xrightarrow{[\text{O}]} \text{CH}_3\text{COOH}$$

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(v)

$$\text{CH}_3\text{COOC}_2\text{H}_5 + \text{NaOH} \longrightarrow \text{CH}_3\text{COONa} + \text{C}_2\text{H}_5\text{OH}$$

(Sodium ethanoate + Ethanol)

Source: Carbon and its Compounds, Chapter 4, Sections 4.2.2, 4.4

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Explanation
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