AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Mica acts as an insulator in electrical devices. Its excellent di-electric strength, low power loss factor, and resistance to high voltage prevent current from leaking between components, protecting circuits.
Copper, being malleable, ductile, and a good conductor, is used in electrical cables and electronics to carry current efficiently.
Both are essential: copper transmits electricity, while mica controls and contains it — making safe, functional electrical systems impossible without either.
Source: Chapter 5 — Non-Metallic Minerals; Non-Ferrous Minerals
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The examiner wants you to identify the specific property of each mineral and then address the "why both are needed" part — that's the analytical step many students skip. The key insight is that an electrical industry needs both conduction (copper) and insulation/control (mica); they are complementary, not contradictory. Stick to textbook terms: "di-electric strength," "insulating properties," "malleable," "ductile," "good conductor." Don't write general facts about where they are found — the question is about their role.