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Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [5] deep exam-ready
(a) With the help of labelled ray diagrams, show the formation of image by a concave mirror when the object is (i) beyond C and (ii) between P and F. (b) State the nature, position and relative size of the image in each case. (c) A dentist uses a concave mirror to examine a tooth. The tooth is placed 2 cm from the mirror. The focal length of the mirror is 8 cm. Find the position and magnification of the image. Explain why this is suitable for the dentist's purpose.
Generated by claude-sonnet-4-6 · 2026-06-26 01:13 · grounding rag
Model Answer

(a) Ray Diagrams:

Case (i) — Object beyond C:

```
Object C F P
↓ | | |
----[ray 1→ parallel to axis → reflects through F]
----[ray 2→ through C → reflects back along same path]
Image (between F and C, inverted, diminished)
```

Draw two rays: one parallel to the principal axis (reflects through F) and one through C (reflects back along the same path). They meet between F and C to form a real, inverted, diminished image.

Case (ii) — Object between P and F:

Draw one ray parallel to the axis (reflects through F) and one through C. The reflected rays diverge; when extended behind the mirror they meet to form a virtual, erect, enlarged image behind the mirror.

(b) Nature, position and size of image:

| Position of Object | Position of Image | Size | Nature |
|---|---|---|---|
| Beyond C | Between F and C | Diminished | Real, Inverted |
| Between P and F | Behind the mirror | Enlarged | Virtual, Erect |

(c) Calculation:

Given: u = −2 cm, f = −8 cm

Using mirror formula: $\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f}$

$$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{-8} - \frac{1}{-2} = -\frac{1}{8} + \frac{1}{2} = \frac{3}{8}$$

$$v = +\frac{8}{3} \approx +2.67 \text{ cm}$$

Magnification: $m = -\dfrac{v}{u} = -\dfrac{+8/3}{-2} = +\dfrac{4}{3} \approx +1.33$

The image is virtual, erect, and magnified (m > 1). Since the tooth is between P and F, the concave mirror forms an enlarged, erect, virtual image behind the mirror, allowing the dentist to see a clear, magnified view of the tooth. This makes it very suitable for dental examination.

Source: Chapter 9, Section 9.2.1 and 9.2.2

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Explanation
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.