AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
(i) Angle of Refraction:
Using Snell's law: $n = \dfrac{\sin i}{\sin r}$
$$1.5 = \frac{\sin 45°}{\sin r} = \frac{0.707}{\sin r}$$
$$\sin r = \frac{0.707}{1.5} = 0.471$$
$$r = \sin^{-1}(0.471) \approx 28.1°$$
(ii) At the second parallel surface, the ray goes from glass (denser) to air (rarer), so it bends away from the normal. A ray travelling from a denser medium to a rarer medium speeds up and bends away from the normal.
(iii) Speed of light inside glass is less than in air. Since $n = \dfrac{c}{v}$, and $n = 1.5 > 1$, the speed in glass $v = \dfrac{3 \times 10^8}{1.5} = 2 \times 10^8$ m s$^{-1}$.
Source: Chapter 9, Sections 9.3.1 and 9.3.2
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