📚 CBSE Grade-10 Study Guide
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Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [3] medium exam-ready
A ray of light enters a glass slab (refractive index 1.5) at an angle of incidence of 45°. (i) Calculate the angle of refraction inside the glass. (ii) When the ray reaches the second parallel surface of the slab, does it bend towards or away from the normal? Give a reason. (iii) How does the speed of light inside the glass compare to its speed in air?
Generated by claude-sonnet-4-6 · 2026-06-26 01:12 · grounding rag
Model Answer

(i) Angle of Refraction:

Using Snell's law: $n = \dfrac{\sin i}{\sin r}$

$$1.5 = \frac{\sin 45°}{\sin r} = \frac{0.707}{\sin r}$$

$$\sin r = \frac{0.707}{1.5} = 0.471$$

$$r = \sin^{-1}(0.471) \approx 28.1°$$

(ii) At the second parallel surface, the ray goes from glass (denser) to air (rarer), so it bends away from the normal. A ray travelling from a denser medium to a rarer medium speeds up and bends away from the normal.

(iii) Speed of light inside glass is less than in air. Since $n = \dfrac{c}{v}$, and $n = 1.5 > 1$, the speed in glass $v = \dfrac{3 \times 10^8}{1.5} = 2 \times 10^8$ m s$^{-1}$.

Source: Chapter 9, Sections 9.3.1 and 9.3.2

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Explanation
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.