AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
(D) –25 cm, concave
$f = \frac{1}{P} = \frac{1}{-4.0} = -0.25\ \text{m} = -25\ \text{cm}$. Negative focal length indicates a concave (diverging) lens.
Use $f = \frac{1}{P}$, always convert to cm. A negative power → negative focal length → concave lens. Examiners expect the formula, substitution, and correct identification of lens type.