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Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [3] medium thorough-understanding
A concave mirror has a radius of curvature of 40 cm. An object 5 cm tall is placed 20 cm in front of it. Using the mirror formula, find the position and size of the image. State its nature (real/virtual) and orientation (erect/inverted).
Generated by claude-sonnet-4-6 · 2026-06-26 01:12 · grounding rag
Model Answer

Given: R = 40 cm, so f = R/2 = −20 cm (concave mirror); object height h = 5 cm; u = −20 cm

Mirror formula: $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

$$\frac{1}{v} + \frac{1}{-20} = \frac{1}{-20}$$

$$\frac{1}{v} = -\frac{1}{20} + \frac{1}{20} = 0 \implies v = \infty$$

Since the object is placed exactly at the focus (u = f = −20 cm), the reflected rays are parallel and no image is formed at a finite distance (image at infinity).

Magnification: $m = -\frac{v}{u}$ → undefined (image at infinity).

Nature: Real and inverted (for any finite screen, image cannot be obtained).

Source: Light – Reflection and Refraction, Table 9.1; Mirror Formula section

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Explanation
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.