AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Given: f = +10 cm (convex lens), u = −30 cm
Using the lens formula:
$$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$$
$$\frac{1}{v} - \frac{1}{-30} = \frac{1}{10}$$
$$\frac{1}{v} = \frac{1}{10} - \frac{1}{30} = \frac{3-1}{30} = \frac{2}{30}$$
$$v = +15 \text{ cm}$$
The image is formed 15 cm on the other side of the lens.
Since v is positive, the image is real and inverted. (The object is placed between F₁ and 2F₁, so the image is beyond 2F₂.)
Source: Light – Reflection and Refraction, Chapter 9, Section 9.3.6
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