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Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [1] medium thorough-understanding
A current-carrying rod is placed in a magnetic field. When the current in the rod is doubled and the strength of the magnetic field is also doubled, how does the force on the rod change compared to the original force?
Generated by claude-sonnet-4-6 · 2026-06-26 01:12 · grounding rag
Model Answer

The force becomes 4 times the original force, since force on a current-carrying conductor is directly proportional to both current and magnetic field strength (F ∝ I × B). Doubling both doubles each factor: 2 × 2 = 4.

Explanation

The key concept is that the force on a current-carrying conductor is proportional to the product of current (I) and magnetic field (B). The textbook states that displacement (force) is largest at right angles and depends on both current and field strength. Since both are doubled, the force multiplies: F_new = (2I)(2B) = 4F. Examiners expect the factor "4 times" stated clearly with brief reasoning.

Source: Chapter 12, Section 12.3 — Force on a Current-Carrying Conductor in a Magnetic Field.

Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.