Science (086) — AI-generated practice question

Calculation:

Current drawn by the geyser:

$$I = \frac{P}{V} = \frac{3000 \text{ W}}{220 \text{ V}} \approx 13.6 \text{ A}$$

Result: The fuse will blow/melt.

Reason: The geyser requires ~13.6 A, which far exceeds the 5 A rating of the fuse. As per the domestic circuit, appliances like geysers require a 15 A circuit, not a 5 A circuit. The excess current causes Joule heating in the fuse wire, which melts it and breaks the circuit, preventing damage to the wiring and appliance.

Source: Chapter 12, Section 12.4 — Domestic Electric Circuits

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• The key formula here is $I = P/V$. Always show this step explicitly — it earns a mark.
• The second mark is for stating the fuse melts/blows, and the third for explaining why (current exceeds fuse rating → Joule heating melts fuse wire).
• The textbook (Section 12.4) explicitly states geysers need a 15 A circuit; connecting to a 5 A circuit causes overloading — use this fact to strengthen your answer.
• Don't forget units in your calculation.