AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
The student is incorrect. In a parallel circuit, the same voltage (20 V) acts across both resistors, but current depends on resistance: higher resistance means lower current (by Ohm's law, $I = V/R$).
Calculation:
$$I_P = \frac{V}{R_P} = \frac{20}{10} = 2 \text{ A}$$
$$I_Q = \frac{V}{R_Q} = \frac{20}{40} = 0.5 \text{ A}$$
Since P has lower resistance (10 Ω), more current flows through P (2 A), not Q (0.5 A). The student confused equal voltage with equal current — while voltage is the same across parallel branches, current is inversely proportional to resistance.
Source: Chapter 11, Section 11.6.2 — Resistors in Parallel
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