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Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [3] medium exam-ready
State Joule's law of heating. An electric iron of resistance 25 Ω is operated at 200 V for 30 minutes. Calculate the heat produced in the iron during this time.
Generated by claude-sonnet-4-6 · 2026-06-26 01:09 · grounding rag
Model Answer

Joule's Law of Heating: The heat produced in a resistor is directly proportional to (i) the square of current (I²), (ii) the resistance (R), and (iii) the time (t) for which current flows.
$$H = I^2 R t$$

Calculation:

Given: R = 25 Ω, V = 200 V, t = 30 min = 30 × 60 = 1800 s

Current, $I = \dfrac{V}{R} = \dfrac{200}{25} = 8$ A

Heat produced:
$$H = I^2 R t = (8)^2 \times 25 \times 1800$$
$$H = 64 \times 25 \times 1800 = 28,80,000 \text{ J} = 2.88 \times 10^6 \text{ J}$$

Source: Chapter 11, Section 11.7 (Heating Effect of Electric Current)

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Explanation
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.