AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Total resistance $R_s = 4 + 6 + 10 = 20\ \Omega$. Current $I = V/R_s = 20/20 = 1\ \text{A}$. Potential difference across 6 Ω $= IR = 1 \times 6 = \mathbf{6\ V}$.
In a series circuit, the same current flows through all resistors. Find total resistance, then current using Ohm's law, then apply $V = IR$ to the individual resistor. Examiner expects all three steps shown briefly even in a 1-mark answer.