📚 CBSE Grade-10 Study Guide
HomeScience (086) (AI practice)

Science (086) — AI-generated practice question

AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.

Q1. [5] medium exam-ready
(a) With the help of a labelled ray diagram, explain the defect of hypermetropia, showing where the image is formed in a hypermetropic eye. (b) Show how the defect is corrected using an appropriate lens. (c) State TWO possible structural reasons why this defect develops.
Generated by claude-sonnet-4-6 · 2026-06-26 01:08 · grounding rag
Model Answer

(a) Defect of Hypermetropia:

Hypermetropia (far-sightedness) is a defect in which a person can see distant objects clearly but cannot see nearby objects distinctly. The near point shifts beyond 25 cm. This happens because light rays from a nearby object are focused behind the retina instead of on it.

Ray Diagram — Hypermetropic Eye:

```
Object → Eye Lens → [Retina] → (Image forms behind retina)
```
(Draw: nearby object, eye with lens, rays converging to a point behind the retina, label: Object, Eye Lens, Retina, Image behind retina)

---

(b) Correction:

A convex (converging) lens of appropriate power is used. It converges the incoming rays before they enter the eye, so the image is now brought forward onto the retina.

Ray Diagram — Corrected Eye:

(Draw: nearby object → convex lens → eye lens → rays converge exactly on retina)

---

(c) Two structural reasons:

  1. The focal length of the eye lens is too long (eye lens is too less curved / less converging).
  2. The eyeball has become too small (shortened eyeball), so the retina is closer to the lens than normal.

Source: Chapter 10, Section 10.2 — Hypermetropia

---

Explanation
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.