AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Lens used: A concave lens (diverging lens) is used to correct myopia.
How it restores normal vision: The myopic person's far point is 2 m (not infinity), meaning the image of distant objects forms in front of the retina. A concave lens of suitable power diverges the incoming light rays before they enter the eye. This shifts the image of the distant object back onto the retina, restoring clear distant vision.
Power of the lens required:
$$P = \frac{1}{f} = \frac{1}{-2} = -0.5 \text{ D}$$
Source: Chapter 10, Section 10.2 – Defects of Vision and Their Correction
---