AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Option B: Ethanol
Ethanol (C₂H₅OH) on oxidation with alkaline potassium permanganate forms ethanoic acid (CH₃COOH).
Source: Oxidation, Chapter 4, Section 4.3.2
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The key is matching the product (ethanoic acid, a 2-carbon compound) to its alcohol precursor. Ethanol is also the 2-carbon alcohol, so oxidation preserves the carbon chain and converts –OH to –COOH. The passage explicitly uses ethanol in Activity 4.5 to demonstrate this oxidation. Other options (methanol = 1C, propanol = 3C, butanol = 4C) would not yield ethanoic acid.