AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
(a) A neutralisation reaction is when an acid reacts with a base to form salt and water, with the evolution of heat. Example: NaOH + HCl → NaCl + H₂O.
The ionic equation for all strong acid–strong base neutralisation reactions is:
$$\text{H}^+(aq) + \text{OH}^-(aq) \rightarrow \text{H}_2\text{O}(l)$$
(b) The blue-green solution indicates formation of copper sulphate, so metal oxide X is copper(II) oxide (CuO).
$$\text{CuO}(s) + \text{H}_2\text{SO}_4(aq) \rightarrow \text{CuSO}_4(aq) + \text{H}_2\text{O}(l)$$
CuO is a basic oxide because it reacts with an acid (H₂SO₄) to form salt and water only, showing no acidic character.
(c) Zinc reacts with sodium hydroxide as follows:
$$\text{Zn}(s) + 2\text{NaOH}(aq) \rightarrow \text{Na}_2\text{ZnO}_2(aq) + \text{H}_2(g)$$
Difference: When a metal reacts with an acid, hydrogen gas is displaced and a salt of the acid is formed. Here, zinc reacts with a base (NaOH) and still produces hydrogen gas, forming sodium zincate. This shows zinc is an amphoteric metal — it can react with both acids and bases, unlike most metals which react only with acids.
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